B=(5a)^2

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Solution for B=(5a)^2 equation: 



=(5B)^2

We move all terms to the left:

-((5B)^2)=0

determiningTheFunctionDomain
-5B^2=0

a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$B=\frac{-b}{2a}=\frac{0}{-10}=0$

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